Joseph throws a dice. What is the probability that he will get an odd number?


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Answer:

 

1
2
 

Step by Step Explanation:
  1. Let us assume S, E, and P are the Sample Space, Event and Probability of getting an odd number by throwing the dice, respectively.
    S = {1, 2, 3, 4, 5, and 6}
    E = {1, 3, 5}
  2. P(E) =  
    n(E)
    n(S)
     
    (Since, P(E) is the probability of getting an event E, n(E) is the number of elements in the event E and n(S) is the number of elements in the sample space S )
    P(E) = 
    3
    6
     
    =  
    1
    2
     
  3. Hence, the probability of getting an odd number is  
    1
    2
         .

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